Help with graph please

Mathematics

1 answer:

Ymorist [56]3 years ago

4 0

Answer:

SO... not so tricky just go up by 10! 1= 10 2= 20 and make the y axis go up to ten. Also reverse the 10 and 1000 in your bottom x axis.

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I don't know what's it asking me. what should I do?

Anton [14]

$n$ - a number
$n^2$ - its square
$n+n^2$ - the sum
$\leq$ - less than or equal
negative three - I don't have to explain this one, do I?

$n+n^2\leq-3$ - the sum of a number and its square is less than or equal negative three

6 0

2 years ago

Read 2 more answers

Given that f(–2.4) = -1 and f(-1.9) = -8, approximate f'(-2.4). f'(-2.4)

lora16 [44]

Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
Algebra I

Coordinate Planes

Coordinates (x, y)

Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Functions

Function Notation

Calculus

Differentiation

Derivatives
Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the tangent line.

Step 1: Define

Identify.

f(-2.4) = -1

f(-1.9) = -8

Step 2: Differentiate

Simply plug in the 2 coordinates into the slope formula to find slope m.

[Derivative] Set up [Slope Formula]: $\displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}$
Substitute in coordinates: $\displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}$
Evaluate: $\displaystyle f'(-2.4) \approx -14$