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SSSSS [86.1K]
3 years ago
10

The price of a visit to the dentist is calculated according to the formula 50+100n where n is the number of cavities the dentist

finds. On your last visit to the dentist, 2 cavities were found. What was the cost of your visit ?
Mathematics
1 answer:
Vsevolod [243]3 years ago
8 0
So you would First find out N which would be 2. So you do 50+100and that would be 150. Then you do 150×2 and that is 300. So the answer is 300!
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Erika bought 3 kilograms of cinnamon red hots and 1 kilogram of gummy bears for $21.00. Meanwhile, Irene bought 3 kilograms of c
grin007 [14]
Erika $21
3k of cinnamon
1g of gummies

Irene $39
3k of cinnamon
3k of gummies

c= cost of 1 kilogram of cinnamon
g= cost of 1 kilogram of gummies

Erika's Equation
3c + 1g= $21

Irene's Equation
3c + 3g= $39

Solve for one variable in equation one and substitute it in the other equation.

3c + 1g= 21
subtract 3c from both sides
g= 21 - 3c

Substitute g=21 - 3c in equation
3c + 3g= $39
3c + 3 (21 - 3c)= 39
multiply all in parentheses
3c + 63 - 9c= 39
63 - 6c= 39
subtract 63 from both sides
-6c= -24
c= $4

Substitute c=4 in equation to find g
3c + g= 21
3(4) + g= 21
12 + g= 21
subtract 12 from both sides
g= $9

ANSWER: The price of 1 kilogram of cinnamon red hots is $4. The cost of 1 kilogram of gummies is $9.

Hope this helps! :)
3 0
3 years ago
Solve r + (-8) = 10<br><br> ———————-
Yuliya22 [10]

Answer:

r = 18

Step-by-step explanation:

r -8 = 10

r -8 + 8 = 10 + 8

r = 18

4 0
3 years ago
At one point the average price of regular unleaded gasoline was ​$3.39 per gallon. Assume that the standard deviation price per
irinina [24]

This question was not written completely

Complete Question

At one point the average price of regular unleaded gasoline was ​$3.39 per gallon. Assume that the standard deviation price per gallon is ​$0.07 per gallon and use​ Chebyshev's inequality to answer the following.

​(a) What percentage of gasoline stations had prices within 3 standard deviations of the​ mean?

​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean? What are the gasoline prices that are within 2.5 standard deviations of the​ mean?

​(c) What is the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​?

Answer:

a) 88.89% lies with 3 standard deviations of the mean

b) i) 84% lies within 2.5 standard deviations of the mean

ii) the gasoline prices that are within 2.5 standard deviations of the​ mean is $3.215 and $3.565

c) 93.75%

Step-by-step explanation:

Chebyshev's theorem is shown below.

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

2) At least 75% or 3/4 of the data for a set of numbers lies within 2 standard deviations of the mean. The number could be greater.μ - 2σ and μ + 2σ.

3) At least 88.89% or 8/9 of a data set lies within 3 standard deviations of the mean.μ - 3σ and μ + 3σ.

4) At least 93.75% of a data set lies within 4 standard deviations of the mean.μ - 4σ and μ + 4σ.

​

(a) What percentage of gasoline stations had prices within 3 standard deviations of the​ mean?

We solve using the first rule of the theorem

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

Hence, k = 3

1 - 1/k²

= 1 - 1/3²

= 1 - 1/9

= 9 - 1/ 9

= 8/9

Therefore, the percentage of gasoline stations had prices within 3 standard deviations of the​ mean is 88.89%

​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean?

We solve using the first rule of the theorem

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

Hence, k = 3

1 - 1/k²

= 1 - 1/2.5²

= 1 - 1/6.25

= 6.25 - 1/ 6.25

= 5.25/6.25

We convert to percentage

= 5.25/6.25 × 100%

= 0.84 × 100%

= 84 %

Therefore, the percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean is 84%

What are the gasoline prices that are within 2.5 standard deviations of the​ mean?

We have from the question, the mean =$3.39

Standard deviation = 0.07

μ - 2.5σ

$3.39 - 2.5 × 0.07

= $3.215

μ + 2.5σ

$3.39 + 2.5 × 0.07

= $3.565

Therefore, the gasoline prices that are within 2.5 standard deviations of the​ mean is $3.215 and $3.565

​(c) What is the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​?

the mean =$3.39

Standard deviation = 0.07

Applying the 2nd rule

2) At least 75% or 3/4 of the data for a set of numbers lies within 2 standard deviations of the mean. The number could be greater.μ - 2σ and μ + 2σ.

the mean =$3.39

Standard deviation = 0.07

μ - 2σ and μ + 2σ.

$3.39 - 2 × 0.07 = $3.25

$3.39 + 2× 0.07 = $3.53

Applying the third rule

3) At least 88.89% or 8/9 of a data set lies within 3 standard deviations of the mean.μ - 3σ and μ + 3σ.

$3.39 - 3 × 0.07 = $3.18

$3.39 + 3 × 0.07 = $3.6

Applying the 4th rule

4) At least 93.75% of a data set lies within 4 standard deviations of the mean.μ - 4σ and μ + 4σ.

$3.39 - 4 × 0.07 = $3.11

$3.39 + 4 × 0.07 = $3.67

Therefore, from the above calculation we can see that the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​ corresponds to at least 93.75% of a data set because it lies within 4 standard deviations of the mean.

4 0
3 years ago
PLEASE HELP ILL REWARD BRAINLIST
kodGreya [7K]

Answer: (2,1)

Hope it helps <3

7 0
3 years ago
Read 2 more answers
Xyz is translated 4 units up and 3 units left to yield xyz.what is the distance between any two corresponding points on xyz and
vagabundo [1.1K]
This would be ( using the Pythagoras theorem) = sqrt (3^2 + 4^2)  = sqrt 25

= 5 units  (answer).
4 0
3 years ago
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