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kykrilka [37]
3 years ago
8

What is the measure of arc ADB? What is the length of arc ADB? What is the area of the shaded region?

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0
What is the measure of arc ADB?
 The measure of the arc for this case is given by the following angle:
 theta = 360-90
 theta = 270 degrees

 What is the length of arc ADB? 

 The arc length is given by:
 s = R * theta
 Substituting values:
 s = 15 * (270 * (pi / 180))
 s = 70.69 m

 What is the area of the shaded region?

 The area of the shaded region is:
 A = (s' / s) * (pi) * (r ^ 2)
 Substituting values:
 A = (270/360) * (3.14) * (15 ^ 2)
 A = 529,875 m ^ 2
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A cab company charges a flat fee of $5.00 and then an additional $0.45 per mile. Write an equation expressing the cost of a ride
Oliga [24]

The equation representing the cost of the ride is R = $5 + $0.45dd.

<h3>What is flat fee? </h3>

The flat fee charged is the fixed cost. This cost remains constant regardless of the distance travelled. The additional fee is the variable cost. It increases with the distance travelled.

<h3> Derivation of the equation that represents cost of the ride.</h3>

Total cost = fixed cost +  (variable cost x miles driven)

R = $5 + $0.45dd

To learn more about flat fees, please check: brainly.com/question/25879561

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3 years ago
How many terms are in the expansion (a+b)19
astra-53 [7]

Answer:

There are 2 ters because you would distribute the 19 to the a and the b to make it 19a + 19b, which has 2 terms

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What is the is f(x)=8x^2+4x written in the vertex form?
erastovalidia [21]

Answer:

f(x)=8-4

Step-by-step explanation:

f(x) = 8 (x+1/4)^2-1/2

f(x) = 8 – (x+1/4)^2-1/16

f(x) = 8 – 2

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3 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

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3 years ago
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