Answer: g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Step-by-step explanation:
Given functions: and
When x=0, and
∴ at x=0, g(x)=h(0)
Therefore the statements "For any value of x, g(x) will always be greater than h(x)." and "For any value of x, h(x) will always be greater than g(x)." are not true.
When x=-1, and
∴g(x) > h(x) for x = -1. ......................(1)
When x=3, and
∴ g(x) > h(x) for x = 3....................(2)
⇒g(x) < h(x) for x = 3. is not true.
From (1) and (2),
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).