All categories

2 years ago

Which is an example of a statistical question?

Mathematics

2 answers:

Phantasy [73]2 years ago

6 0

<h2>Answer:</h2>

The example of a statistical question is:

Question 4: How old are the students in math class?

<h2>Step-by-step explanation:</h2>

<u>Statistical question--</u>

A statistical question is one which is based over the data which is sampled or collected such that there is a variability in the data.

Here the first three questions i.e.

Question 1 How old am I?

Question 2 How old is the teacher?

Question 3 How old will I be after my next birthday?

are not based over the sample these are based over a individual and not over the data or population. Hence, they are invalid.

The statistical question is:

D) Question: 4

Vikki [24]2 years ago

5 0

Hey there, Damonealy!

The correct answer should be D since you are talking about multiple amount of data. As you can see, question number 1-3 are talking about the age of a single person but question D is talking about the ages of multiple students which can be used in a statistic.

Thank you for using Brainly.
See you soon!

You might be interested in

Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th

jonny [76]

Answer:

The answer is $\sqrt{\frac{6}{5}}$

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

$\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy$

Solving:

$\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy$

$[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.$

Replacing the limits:

$6*\frac{1}{3} =2$

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ $\frac{1}{m}$

Solving the double integral with these new limits we have:

$\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy$

This part is a little bit tricky so let's solve the integral first for dy:

$\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx$

Replacing the limits:

$\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx$

Solving now for dx:

$[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.$

Replacing the limits:

$\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}$

As I mentioned before, this volume is equal to 1, hence:

$\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }$

3 0

2 years ago

Julio paid $27 to rent a scooter for 4 hours. Elsie paid $42 for 7 hour. Assuming the relationship is linear, write an equation

Bezzdna [24]

Answer:

The answer is B.) mate

8 0

2 years ago

PLEASE HELP ASAP

pishuonlain [190]

You have that:

1. By definition, a binomial is a polynomial formed by two terms.
2. A quintic binomial is a binomial of degree 5. This means that its highest exponent is 5.
3. Keeping this on mind, you must identify which binomial has degree 5.
4. As you can see, the expression <span>3x^5+2 is a binomial, because it has two terms and the highest degree is 5.
5. Thefore, the answer is: </span>3x^5+2

8 0

2 years ago

Consider the equation: -2x+5y=20

raketka [301]

Answer:

$- 2x + 5y = 20 \\ 5y = 2x + 20 \\ y = \frac{2}{5} x + 4 \\ slope = \frac{2}{5} \\ y - intercept = 4$

8 0

2 years ago

Please help me. this is hard

allochka39001 [22]

Since it is a square that means each side is equal.
The perimeter is 24, and since there is four sides we would divide it by four to find the length of each side.

24/4 = 6

Each side is 6.
By looking at the picture, one side of the square, is the length of the radius.

The radius of the square is 6.

The only thing left to do is to find the circumference.
The circumference formulas are:

C = $\pi$ d
C = 2 $\pi$ r

We can use the first one Diameter x pi (3.14)
To find the diameter we would just multiply the radius by two.

6 x 2 = 12

Diameter = 12

So multiply it by pi

12 x 3.14 = 37.68
or D 12 $\pi$

7 0

2 years ago