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3 years ago

Hector needs to find the product of 23 and 97. Which shows a way to Hector could find the product?

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

23 x 97

You didn't provide the options so I chose to show the Array Method:

20 + 3

90 1800 270 = 2070

+ +

7 140 21 = 161

2231

Answer: 2231

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The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago

18.

chubhunter [2.5K]

A bakers dozen is 12 which would be $0.41 for each cookie. If you meant 13, it would be $0.38. All you have to do is divide 4.94 by the amount of cookies

7 0

2 years ago

Q= QUADRADO

Lubov Fominskaja [6]

Answer
C x Q x T = ? = 24

6 0

3 years ago

Explain-Carmen is making homemade root beer for an upcoming charity fundraiser.

NeTakaya

Answer:

1.5lb/ounces

Step-by-step explanation:

Given:

Mass of dry ice Carmen uses = 12lb

Mass of root beet = 8ounces

Unknown:

Ratio/Proportional constant for number of pounds to number of ounces of root beer extract = ?

Solution:

To solve this problem,

Ratio = $\frac{number of pounds of dry ice}{Ounce of root beer}$

Ratio = $\frac{12lb}{8ounces}$ = 1.5lb/ounces

6 0

3 years ago

Solve 5x^2 - 7x+2 -0 by completing the square. What are the solutions?

trapecia [35]

5x² - 7x + 2 = 0

5(x² - 7/5 x) + 2 = 0

5(x² - 7/5 x + 49/100 - 49/100) + 2 = 0

5(x² - 2 • 7/10 x + (7/10)²) - 49/20 + 2 = 0

5(x - 7/10)² - 9/20 = 0

5(x - 7/10)² = 9/20

(x - 7/10)² = 9/100

x - 7/10 = ± √(9/100)

x - 7/10 = ± 3/10

x = 7/10 ± 3/10

x = 10/10 = 1 or x = 4/10 = 2/5

6 0

2 years ago