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Tcecarenko [31]
3 years ago
15

Simplify: - 3/2(4x + 3)

Mathematics
1 answer:
Korolek [52]3 years ago
3 0
1) -3/2 × 4x = -6x
2) -3/2 × 3 = -9/2

Answer: -6x−​9/2
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What is the value of this expression?<br><br> ​ 1.5(−2.4+(−5.3))
Ahat [919]

Answer:

-11.55

Step-by-step explanation:

(to get the numbers out of the brackets you have to multiply all the numbers in the brackets to the number that is there, and in this case its 1.5)

1.5x(-2.4)= -3.6

1.5×(-5.3)= -7.95

after that, you add them (because there is a plus sign, not a minus, multiplication sign or a division sign.)

-7.95+ -3.6= -11.55

answer= -11.55

7 0
3 years ago
The measure of angle A is 4 degrees greater than the measure of angle B. The two angles are complementary. Find the measure for
svetlana [45]
Given: 
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary

Complementary angles have a sum of 90°

Angle A = x + 4° ; Angle B = x

x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.

Angle A = x + 4° ⇒ 43° + 4 = 47°

Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°

Angle D = 5x ; Angle E = x

5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30°  Angle E.

Angle D = 5x = 5(30) = 150°
6 0
3 years ago
Read 2 more answers
When the transformation (x,y) → (x + 10, y + 5) is
serious [3.7K]

Answer:

its 3.05

Step-by-step explanation:

5 0
3 years ago
Which angle is an alternate interior angle to 8?
Rina8888 [55]

Answer:

<5

Step-by-step explanation:

Interior angle Kasi eh hihi

5 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
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