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hram777 [196]
3 years ago
7

BEST GETS BRAINLIEST Proof for Pythagoras Theorem (I’ll take multiple different approaches) Please make it logical/satisfying.

Mathematics
1 answer:
puteri [66]3 years ago
8 0

Answer:

Proofs for Pythagoras Theorem usually use visual/geometry approaches. I don't post pictures in my answers, so I will present a linear algebra approach. You can see it in the blog posted by Professor Terence Tao.

Note that there are several elegant proofs using animations and drawings, but this is just personal.

I've seen this some time ago, it is really interesting proof.

It states that a^2+b^2=c^2 is equivalent to the statement that the matrices

%\begin{pmatrix}a & b \\ -b & a%\end{pmatrix}%    \begin{pmatrix}a& b  \\-b & a\\\end{pmatrix} and \begin{pmatrix}c & 0\\0 & c \\\end{pmatrix} have the same determinant.

The determinant of the first matrix is a^2+b^2

The determinant of the second matrix is c^2

Once the linear transformations associated with these matrices differ by rotation, we claim that

a^2+b^2=c^2

 

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Answer:

27 problems are remaining to solve

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3 years ago
Write the vector below in component form.<br> PQ where P=(-4,1) Q=(-9,-5)
shepuryov [24]

Answer:

-14

Step-by-step explanation:

6 0
3 years ago
How many different 2-digit numbers are there with the following property:the tenth digit is greater than the units digit?
Serggg [28]

Answer:

45

Step-by-step explanation:

Simply start by listing out the numbers from smallest to largest.

We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45

7 0
2 years ago
it is 6.09 pm the movie starts at 6:30 pm. while standing in the line for the movie, you count 146 people in front of you. nine
Brilliant_brown [7]
<h2>Answer:You can buy a ticket.</h2>

Step-by-step explanation:

It is given that 9 people bought tickets in 70 seconds.

So,\frac{9}{70} people can buy tickets in a second.

It is given that the current time is 6:09pm and movie starts at 6:30pm.

So there is 30-9=21minutes until movie starts.

In 21 minutes,the number of persons that can buy tickets are \frac{9}{70}\times 21\times 60=162.

So,162 people can buy tickets in 21 minutes.

Since there are only 146 people in front of you,you can buy a ticket.

8 0
3 years ago
How do I do this please explain step by step !!
MArishka [77]

Answer:

you will need a graph

Step-by-step explanation:

so you will need to find -4 on the x axis and find 4 on the y axis then join the points and the same with -9 on x axis and 6 on y axis  then the same on all of them

4 0
3 years ago
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