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3 years ago

Factor the trinomial completely. a^4 -2a^2 - 35

Mathematics

1 answer:

valentina_108 [34]3 years ago

8 0

Answer:

(a^2+5)(a^2-7)

Step-by-step explanation:

a^4 -2a^2 - 35=
a^4-2a^2+1-36=
(a^2-1)^2-6^2=
(a^2-1+6)(a^2-1-6)=
(a^2+5)(a^2-7)

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3w + 2 = 7w Please help

mash [69]

3w +2 =7w
-3w -3w
2=4w
Divide each side by 4
1/2=w

Check your answer:
3 (1/2) + 2 = 7 (1/2)
(3/2) + (4/2) = (7/2)
(7/2) = (7/2)

Hope this helps.

8 0

3 years ago

Read 2 more answers

HELPP PLEASE ASAP Use the Pythagorean theorem to find the missing length in the right triangle

qwelly [4]

Answer:

c = 10

Step-by-step explanation:

The pythagoras theorem :

a² + b² = c²

a = 6 and b = 8

6² + 8² = c²

36+64 = c²

100 = c²

c = √100

c= 10

Hope this helped and brainliest please

3 0

2 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

2 years ago

You fill 1/4 of a 5 gallon bucket. how many more gallons of water will you need to fill the bucket

Bess [88]

1/4 of a five gallon bucket is 1 1/4 gallons.

5-1 1/4=3 3/4 gallons left to fill.

Answer: 3 3/4 gallons

8 0

3 years ago

Given line AB and point O on that line, any ray that can be drawn with its endpoint at O can be put into a one- to-one correspon

natima [27]

Answer:

Protractor

Step-by-step explanation:

A POSTULATE, LAW OR THEORY SHOULD NEVER BE ALTERED

∴ The protractor postulate states that the measurement of an angle between two rays can be designated as a unique number, and this number would be between 0 and 180 degrees, Hence for every angle A, there corresponds a positive real number less than or equal to 180. This postulate guarantee the use of a protractor to measure angles.

Hence, Given line AB and point O on that line in such a way that any ray that can be drawn with its endpoint at O can be put into a one- to-one correspondence with the real numbers between 0 and 180 is a statement that explains Protractor's Postulate.

4 0

3 years ago