domain is the 1st entry and range is sevond. entry
Answer:
b
Step-by-step explanation:
105 - 32 = 73
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<h3>Answer : y = ⅚x - 3</h3>
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<h3>Known</h3>
x1 = 6
y1 = 2
x2 = (-6)
y2 = (-8)
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<h3>Question</h3>
Equation of the line (y = mx + c)
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<h3>Way to do</h3>
#First, you find the gradient (m)
#Now use the formula of equation of the line
y - y1 = m(x - x1)
y - 2 = ⅚(x - 6)
y - 2 = ⅚x - 5
y = ⅚x - 5+2
y = ⅚x - 3
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Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
3.6 divided by 9= 0.4
Answer is 0.4km
