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hjlf
3 years ago
10

at video shack movie rentals cost $3.99 each. the cost of renting three movies and one video game is $.11 less than the cost of

renting five video games. how much does renting a video game cost?
Mathematics
1 answer:
damaskus [11]3 years ago
4 0
x-\ cost\ of\ renting\ video\ game\\
y-\ cost\ of\ tenting\ movie\\\\
3y+1x+11=5x\\
y=3,99\\\\
3*3,99+x+11=5x\\
11,97+x+11=5x\ \ \ | subtract\ x\\
22,97=4x\ \ \ | divide\ by\ 4\\
x=5,7425\$\\\\
For\ renting\ video\ game\ you\ will\ pay\ 5,7425\$.
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STALIN [3.7K]

Answer:

32 muffins

Step-by-step explanation:

one cup of milk will make 32 muffins

you can set up a proportion of milk/muffins = milk/muffins

let 'x' = number of muffins made from one cup of milk

5/8 ÷ 20 = 1 ÷ x

cross-multiply to get 5x = 20(8)

5x = 160

x = 32

6 0
2 years ago
A company sells boxes of small blue pom-poms (b) for $42 and boxes of large orange pom-poms (p) for $52. They make batches of sm
Strike441 [17]

Answer:

b = 40 - p

42b + 52p = 350

Step-by-step explanation:

Given : No. of small blue pom-pom boxes = b

            No. of large orange pom-poms    = p

           cost of 1 box of blue pom pom = $42

           cost of one  large orange pom-pom box = $52

Solution:

Since we are given that the company has only 40 boxes

⇒b+p=40

⇒b=40-p

Since cost of 1 box of blue pom pom = $42

So, cost of b box of blue pom pom = $42b

Since,cost of one  large orange pom-pom box = $52

So,cost of p  large orange pom-pom box = $52p

We are also given that the company plan to make $350

⇒42b+52p=350

Hence Option b is correct

b = 40 - p

42b + 52p = 350

4 0
3 years ago
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Vadim26 [7]

Answer:

(6x² - 5)(x² + 2)

Step-by-step explanation:

Given

6x^{4} - 5x² + 12x² - 10 ( factor the first/second and third/fourth terms )

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= (6x² - 5)(x² + 2)

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3 years ago
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Answer:

Step-by-step explanation:

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Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

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