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Alekssandra [29.7K]
3 years ago
12

The motion of a simple spring hanging from the ceiling can be modeled with a cosine function. The bottom of the spring has a max

imum height of 7 feet 4 inches and a minimum height of 6 feet 2 inches from the floor. It takes 2 seconds for the spring to expand from its minimum length to its maximum length. What is a cosine function that models the spring’s length in inches above and below its average, resting position? Express the model as a function of time in seconds
Mathematics
1 answer:
musickatia [10]3 years ago
3 0
To get the average resting position of the spring, we must subtract the minimum from the maximum height of the spring with respect to the floor.
So,
7 + (4/12) - [ 6 + (2/12) ] = 1.5 ft

Half of this is where the resting position of the spring is located with respect to the minimum height. If the resting position of the spring is set at 0, then the amplitude of the wave is:
A = 1.5 / 2 = 0.75

Since it takes 2 seconds for the spring to expand from minimum to maximum,
Period = 2 = 2π / n
n = π

The cosine function is:
 y = A cos nt

where y is the distance from the resting position and t is the time in seconds.
y = 0.75 cos πt
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Write the equation of the parabola that has the vertex at point (− 1/2 ,2.3) and passes through the point (5,2 3/4 ).
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The equation of parabola in vertex form is y=0.015(x+0.5)^2+2.3

Step-by-step explanation:

Given coordinate of vertex is (-\frac{1}{2},2.3) and the parabola passes through the point (5,2\frac{3}{4})

So, the equation of parabola in vertex form is

y=a(x-h)^2+k

Where (h,k) is the coordinate of the vertex.

(h,k)=(-\frac{1}{2},2.3)=(-0.5,2.3).\\\\So,\ h=-0.5\ and\ k=2.3

Plugging these value in equation we get,

y=a(x-(-0.5))^2+2.3\\\\y=a(x+0.5)^2+2.3

Now, we will find the value of a

Plug the coordinate (5,2\frac{3}{4})

(x,y)= (5,2\frac{3}{4})\\\\(x,y)=(5,\frac{11}{4})\\\\(x,y)=(5,2.75)

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Plug the value of a in the equation y=a(x+0.5)^2+2.3

So, the equation of parabola with vertex (-\frac{1}{2},2.3) and passes through the point (5,2\frac{3}{4}) is

y=0.0149(x+0.5)^2+2.3 ≅y=0.015(x+0.5)^2+2.3

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3 years ago
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