1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olasank [31]
3 years ago
5

What is 4/5 on the number line below

Mathematics
1 answer:
boyakko [2]3 years ago
6 0
3/4 and 1.............
You might be interested in
Help asap will mark brainliest
Harrizon [31]

Answer:

Step-by-step explanation:

7-5

-21-0

-2/21. the y intercept would be 5, considering the x is 0 on the first pair of coordinates. so y=-2/21x+5, or A

8 0
3 years ago
Read 2 more answers
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
Marco has drawn a line to represent the perpendicular cross-section of the triangular prism. Is he correct? Explain. triangular
evablogger [386]

Answer:

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

The given information are;

A triangular prism lying on a rectangular base and a line drawn along the slant height

A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces

Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).

8 0
3 years ago
Read 2 more answers
Angle 1 and angle 2 form a linear pair.if m angle =5x+9 and m angle 2=3x+11,find the measures of both angels.
lbvjy [14]

Answer: ∠1 = 109°    ∠2 = 71°

<u>Step-by-step explanation:</u>

If the two angles form a linear pair, then their sum is 180°

  ∠1      +     ∠2     = 180°

(5x + 9) + (3x + 11) = 180

              8x + 20  = 180

              8x          = 160

                x          = 20

∠1 = 5x + 9

    = 5(20) + 9

    = 100   + 9

    = 109

∠2 = 3x + 11

     = 3(20) + 11

     =    60  + 11

     =         71

  <u> CHECK:</u>

∠1   + ∠2 = 180°

109° + 71° = 180°

     180°   = 180°  \checkmark

7 0
4 years ago
Helppppppppppppppp pleaseeeeee!
stepan [7]

Answer and Explanation:

You got the first one right!

2. You do the same as you did for the first one: to combine the exponents, you multiple 2 by 9 = 18, and now 18 is your new exponent.

3^{2*9} = 3^{18} , which is the answer

3. Here, you can split up the inside so that you have:

2^5*(y^2)^5= 32*y^{2*5}=32y^{10} , which is the answer

Hope this helps! Please give me brainliest if possible.

3 0
3 years ago
Read 2 more answers
Other questions:
  • Match each expression with an equivalent expression.
    11·1 answer
  • Help please.............
    13·1 answer
  • David works at a nearby electronic store. He makes commission of 15% on everything he sells. If he sells a laptop for $293.00 ho
    10·1 answer
  • The local skating rink pays Mary a fixed rate per pupil plus a base amount to work as a skating instructor. She earns $90 for
    15·1 answer
  • Add and turn to simplest form.
    14·2 answers
  • Need help on this question
    8·1 answer
  • Find the value of x.
    11·1 answer
  • Can anyone help me? Thank you! ^-^​
    8·1 answer
  • Evaluate the sum of 9.1 and 368.8.​
    6·2 answers
  • Hi please help i’ll give brainliest please
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!