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Deffense [45]
3 years ago
12

You visit the Grand Canyon and drop a penny off the edge of a cliff. The distance the penny will fall is 16 feet the first secon

d, 48 feet the next second, 80 feet the third second, and so on in an arithmetic sequence. How far from the cliff will the penny be at 6 seconds after it is initially dropped?
Mathematics
1 answer:
fiasKO [112]3 years ago
5 0
The penny will fall 112 feet the fourth second, 144 feet the fifth second, and 176 feet the sixth second. Therefore, the penny will be a total of 576 feet from the cliff at six seconds.
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PLEASE HELP {It costs 5,700 every one sixth of an hour to build a hotel how many cents does building a hotel cost per second?}
Keith_Richards [23]
One sixth of an hour is 10 minutes.
That means it costs 5,700 every 10 minutes.

Costs 5,700 = 10 minutes

Dive 10 on both sides.

Costs 570 = 1 minute

Lets convert the minute into seconds.

Costs 570 = 60 seconds

Divide both sides by 60.

Costs 9.5 cents = 1 second

Round it off since you can't pay 9.5 cents.

Costs 10 cents = 1 second

This means that every second they pay 10 cents for the hotel. :D


8 0
3 years ago
Identify the solution of each equation from the list given.
sp2606 [1]

Answer:

1.) The answer is b = 6

2.) The answer is t = 10

Step-by-step explanation:

For the first equation in order to fin out the answer we do.....

b + 8 = 14

b + 8 - 8 = 14 - 8

b = 6

For the second question we do....

25 - t = 15

25 - t + t = 15 + t

25 = 15 + t

25 - 15 = 15 + t -15

10 = t

4 0
3 years ago
At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

By substitution:

t^2-5t+4

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
I need to know How to solve it
dezoksy [38]
SohCahToa
Heard of it?
Sine- opposite over hypotenuse 
Cosine-adjacent over hypotenuse 
Tangent- opposite over adjacent 
4 0
3 years ago
-2x+6&lt;4 or 7x+1&lt;-13 what is the answer
Juliette [100K]
I guess x<1 and x<-2

7 0
3 years ago
Read 2 more answers
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