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Marina CMI [18]
3 years ago
6

HELP Find the value of two numbers if their sum is 5 and their difference is 30

Mathematics
2 answers:
vodomira [7]3 years ago
8 0

Answer:

The 2 numbers are -12.5 and 17.5.

Step-by-step explanation:

Let 1 number be x then  x - y  = 30 where the other number is y.

y = x - 30 so the sum is:

x - 30 + x = 5

2x = 35

x = 17.5

and y = 17.5 - 30 = -12.5.

Alex777 [14]3 years ago
3 0

Answer:

17.5 and -12.5

Step-by-step explanation:

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3 years ago
What is the inverse of the function f(x) = 2x - 10?
aliya0001 [1]

Answer:

h(x) = \frac{1}{2} x+ 5

Step-by-step explanation:

To find the inverse of a function, simply switch the 'x' and 'y' variables. Substitute in 'y' in the place of f(x) for this purpose:

y = 2x - 10

Switch positions:

x = 2y - 10

Add '10' to both sides to begin simplifying:

x + 10 = 2y

Divide both sides by 2:

y= \frac{x+10}{2}

This can be rewritten as:

y = \frac{1}{2} x+ 5

Therefore, the inverse of the function is:

h(x) = \frac{1}{2} x+ 5

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3 years ago
Please help me with these!
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Answer:

Step-by-step explanation:

A1. C = 104°, b = 16, c = 25

Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°

A = 180-C-B = 37.6°

Law of Sines: a = c·sinA/sinC ≅ 15.7

A2. B = 56°, b = 17, c = 14

Law of Sines: C = arcsin[c·sinB/b] ≅43.1°

A = 180-B-C = 80.9°

Law of Sines: a = b·sinA/sinB ≅ 20.2

B1.  B = 116°, a = 11, c = 15

Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2

A = arccos{(b²+c²-a²)/(2bc) ≅26.5°

C = 180-A-B = 37.5°

B2. a=18, b=29, c=30

Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°

Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°

C = 180-A-B = 75.3°

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2 years ago
The sales tax in your city is 4.4%, and an item costs $3 before tax.
defon

Answer:

0.132

Step-by-step explanation:

4.4%*3=0.132

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3 years ago
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