So if a cubic box has a side length of 2 ft in order to find the volume we need to cube it or multiply the length times 3 times. so it would be 2x2x2=8. that is the volume of the fiest cube. in order to find the volume of the larger cube first you need to know the length of one of the sides. the base has 4 sides to it that are all equal so you divide 24 by 4 and get 6. then to find the volume you multiply 6 three times since it is also a cubic cube so it would be 6x6x6=216. now you know the volume of each cube so you divide 216 by 8 to find how many times the volume of the small cube would go into the volume of the larger cube and get 27 times.
The given inequality is:
This inequality can be divided in two parts as:
a)
b)
Solving part a:
Solving part b:
Therefore, the solution to the given inequality is
and
. Combining both the ranges we get the solution:
.
In interval notation, this solution can be expressed as [1,5]
That would be D
the first 3 = -12x + 24
bur D = -12x - 24
Answer:
Step-by-step explanation:
A chicken has 2 legs, a pig has four. 13 pigs x 4 legs each = 52
4 chickens x 2 legs each = 8
52+8= 60 legs in total
So there are 13 pigs and 4 chickens
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
