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3 years ago

To the white girl who b a n n e d me i hate u

Mathematics

2 answers:

NISA [10]3 years ago

7 0

Answer:

What happened?

Step-by-step explanation:

son4ous [18]3 years ago

5 0

Answer:

yaaaaaaaaaaaaassss that is not fair

Step-by-step explanation:

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Can somebody help me out with this please?

Crank

Answer:

2 marbles

Step-by-step explanation:

Lana has 3 bags with x marbles in each bag totaling 12 marbles

3x=12

Divide by 3

3x/3 =12/3

x =4

Each bag has 4 marbles

Markus has 3 bags with y marbles totaling 18 marbles

3y =18

Divide each side by 3

3y/3 =18/3

y =6

Each bag has 6 marbles

6-4 =2

There are 2 more marbles in Markus' bags than in Lara's

4 0

3 years ago

Surface integrals using a parametric description. evaluate the surface integral \int \int_{s} f(x,y,z)dS using a parametric desc

DiKsa [7]

You can parameterize $S$ using spherical coordinates by

$\vec s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial\vec v}\times\dfrac{\partial\vec s}{\partial\vec u}=36\langle\cos u\sin^2v,\sin u\sin^2v,\cos v\sin v\rangle$

(I use $\vec s_v\times\vec s_u$ to avoid negative signs. The orientation of the normal vector doesn't matter for a scalar surface integral; you could just as easily use $\vec s_u\times\vec s_v=-(\vec s_v\times\vec s_u)$ .)

Then

$f(x,y,z)=f(6\cos u\sin v,6\sin u\sin v,6\cos v)=36\sin^2v$

and the integral of $f$ over $S$ is

$\displaystyle\iint_Sf(x,y,z)\,\mathrm dS=\int_0^{\pi/2}\int_0^{2\pi}36\sin^2v\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$