●) -2 (3a - 4b)-6a + 3b
-2 (9a-7b)
●) 10 - 6a - 4y - (-2a) + 9y
10 - 6a - 13y - (-2a)
●) 9 (2x-6) - 3 (5-4x
12 (6x-11)
All I did was combine the numbers with the same variable
Answer: -9
Step-by-step explanation:
Divide 63 by -7 and you get -9
Hope this helps :)
Step-by-step explanation:

In this case we have:
Δx = 3/n
b − a = 3
a = 1
b = 4
So the integral is:
∫₁⁴ √x dx
To evaluate the integral, we write the radical as an exponent.
∫₁⁴ x^½ dx
= ⅔ x^³/₂ + C |₁⁴
= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)
= ⅔ (8) + C − ⅔ − C
= 14/3
If ∫₁⁴ f(x) dx = e⁴ − e, then:
∫₁⁴ (2f(x) − 1) dx
= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx
= 2 (e⁴ − e) − (x + C) |₁⁴
= 2e⁴ − 2e − 3
∫ sec²(x/k) dx
k ∫ 1/k sec²(x/k) dx
k tan(x/k) + C
Evaluating between x=0 and x=π/2:
k tan(π/(2k)) + C − (k tan(0) + C)
k tan(π/(2k))
Setting this equal to k:
k tan(π/(2k)) = k
tan(π/(2k)) = 1
π/(2k) = π/4
1/(2k) = 1/4
2k = 4
k = 2
Given that the two functions are
and 
We need to determine the value of 
<u>The value of </u>
<u>:</u>
The value of
can be determined using the formula,
![(f \circ g)(x)=f[g(x)]](https://tex.z-dn.net/?f=%28f%20%5Ccirc%20g%29%28x%29%3Df%5Bg%28x%29%5D)
Substituting
in the above formula, we get;
![(f \circ g)(x)=f[-9x^2-2x+1]](https://tex.z-dn.net/?f=%28f%20%5Ccirc%20g%29%28x%29%3Df%5B-9x%5E2-2x%2B1%5D)
Now, substituting
in the function
, we get;



Thus, the value of
is 
<u>The value of </u>
<u>:</u>
The value of
can be determined by substituting x = -6 in the function 
Thus, we have;




Thus, the value of
is -2797
Hence, Option B is the correct answer.
10x= 23.333333333333
10x-x=9x=21
x=21\9=7/3