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Bezzdna [24]
3 years ago
6

Convert 2 2/3 into an improper fraction​

Mathematics
1 answer:
Furkat [3]3 years ago
5 0

Answer: 8/3

Step-by-step explanation:

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IrinaK [193]
●) -2 (3a - 4b)-6a + 3b
-2 (9a-7b)
●) 10 - 6a - 4y - (-2a) + 9y
10 - 6a - 13y - (-2a)
●) 9 (2x-6) - 3 (5-4x
12 (6x-11)

All I did was combine the numbers with the same variable
3 0
3 years ago
63 = - 7w solution to this equation
Yanka [14]

Answer: -9

Step-by-step explanation:

Divide 63 by -7 and you get -9

Hope this helps :)

8 0
3 years ago
Read 2 more answers
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
4 years ago
Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.
Salsk061 [2.6K]

Given that the two functions are f(x)=9x+2 and g(x)=-9x^2-2x+1

We need to determine the value of (f \circ g)(-6)

<u>The value of </u>(f \circ g)(x)<u>:</u>

The value of (f \circ g)(x) can be determined using the formula,

(f \circ g)(x)=f[g(x)]

Substituting g(x)=-9x^2-2x+1 in the above formula, we get;

(f \circ g)(x)=f[-9x^2-2x+1]

Now, substituting x=-9 x^{2}-2 x+1 in the function f(x)=9x+2, we get;

(f \circ g)(x)=9(-9x^2-2x+1)+2

(f \circ g)(x)=-81x^2-18x+9+2

(f \circ g)(x)=-81x^2-18x+11

Thus, the value of (f \circ g)(x) is (f \circ g)(x)=-81x^2-18x+11

<u>The value of </u>(f \circ g)(-6)<u>:</u>

The value of  (f \circ g)(-6) can be determined by substituting x = -6 in the function (f \circ g)(x)=-81x^2-18x+11

Thus, we have;

(f \circ g)(-6)=-81(-6)^2-18(-6)+11

(f \circ g)(-6)=-81(36)-18(-6)+11

(f \circ g)(-6)=-2916+108+11

(f \circ g)(-6)=-2797

Thus, the value of  (f \circ g)(-6) is -2797

Hence, Option B is the correct answer.

8 0
4 years ago
First estimate. then find each sum 7+11.436+3.08
krok68 [10]
10x= 23.333333333333
10x-x=9x=21
x=21\9=7/3
3 0
4 years ago
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