All categories

3 years ago

Which expression shows the sum 9 + 21 rewritten as a product of the GCF and a sum?

Mathematics

2 answers:

Dima020 [189]3 years ago

8 0

Answer: 3(3+7)

Step-by-step explanation:

3(3+7)

3.3+3.7

9+21

olga_2 [115]3 years ago

3 0

Answer:

3(3 + 7)

Step-by-step explanation:

9 + 21

HCF is 3

3(3 + 7)

You might be interested in

Solve the inequality : 8<=2/3(3y-6)

nydimaria [60]

Answer:

I'm assuming you meant $8\leq \frac{2}{3} (3y-6)$ , if so the answer is $\:y\ge \:6\:$

Step-by-step explanation:

hope this helps :)

5 0

3 years ago

Read 2 more answers

Please help me!<br> Hint: the number is negative

wel

Answer:

$-36$ goes into the box

Step-by-step explanation:

Let the number be $x$ , then

$(m^x)^{\frac{1}{3}}=m^{-12}$

We now use the following property of exponents to simplify the left hand side of the equation.

$(a^m)^n=a^{mn}$

This implies that;

$m^{x\times \frac{1}{3}}=m^{-12}$

$\Rightarrow m^{\frac{x}{3}}=m^{-12}$

Since the bases are the same, we equate the exponents to get;

${\frac{x}{3}=-12$

We now multiply both sides by 3 to get;

$\frac{x}{3}\times 3=-12\times 3$

$\Rightarrow x =-36$

Therefore the number that goes into the box is $-36$

6 0

3 years ago

out of a group of zebras 6/5 times the square root of the number of zebras are playing on the shore of the tank remaining six ar

MatroZZZ [7]

Answer:

Step-by-step explanation:

(6/5)√x = x - 6

(36/25)x = x² - 12x + 36

0 = x² - 13.44x + 36

x = (13.44 ± √(13.44² - 4(1)(36))) / (2(1))

x = (13.44 ± 6.052569702...) / 2

x = 3.69371... zebras

x = 9.74628... zebras

In either case we have some odd fractions of zebras hanging around. This makes me highly suspect that the question is misreported

3 0

2 years ago

A 20 foot ladder is leaning against the side of a building. The bottom of the ladder is 4 feet from the wall. How many feet abov

Semenov [28]

It form a right triangle
legnth of ladder is hypotonuse
bottom of ladder from wall distance is one leg
distance up wall is other leg
a^2+b^2=c^2
c=hypotonuse and a and b are legs

4^2+b^2=20^2
16+b^2=400
minus 16 both sides
b^2=384
sqrt both sides
b=8√6 ft
aprox
b=19.59ft from ground

6 0

3 years ago

Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand

kvasek [131]

Answer:

(a) $\frac{5}{7},\frac{1}{6}$ (b) $\frac{1}{7},\frac{1}{6}$ (c) $\frac{5}{7},\frac{2}{3},\frac{3}{5}$

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with $5$ blue marbles, $1$ white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag $=7$

(a)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(b)

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{7}$

As marble is not returned to bag,

Probability of drawing white marble $=\frac{\text{total white marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(c)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing second blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{4}{6}=\frac{2}{3}$

As marble is not returned to the bag

Probability of drawing third blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{3}{5}$

8 0

3 years ago