1.) Solve the system of equations by method of elimination. Show all your work.

Mathematics

1 answer:

katovenus [111]3 years ago

3 0

Answer:

x=2, y=1

Step-by-step explanation:

Add:

2x+4y=8

+10x-4y=16

------------------

12x=24

Divide by 12 on both sides:

x=2

Substitute x with 2 on either 2x+4y=8 or 10x-4y=16 it doesn't matter it will result in the same answer.

(I will do both of them to prove it but you only need to replace x with one of the equation)

For 2x+4y=8

2(2)+4y=8

4+4y=8

Subtract 4 on both sides

-4+4+4y=8-4

4y=4

Divide 4 on both sides:

y=1

For 10x-4y=16

10(2)-4y=16

20-4y=16

-20+20-4y=16-20

-4y=-4

Divide -4 on both sides:

y=1

The answer for both 2x + 4y = 8 and 10x – 4y = 16 are the same showing that it doesn't matter which equation you replace the number with it will still result you in the same answer

Hope this helps!

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What binomial do you have to add to the polynomial 2x^2+3y^2-5xy+1 to get the following?

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Binomial $-3y^{2}+5xy$ when added to polynomial $2x^{2} +3y^{2} -5xy+1$ gives polynomial that does not contain the variable y .

<h3>What is binomial?</h3>

A mathematical expression consisting of two terms connected by a plus sign or minus sign .

Example: x + 2 is a binomial, where x and 2 are two separate terms.

<h3>What is polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer

According to the question

polynomial $2x^{2} +3y^{2} -5xy+1$

when added with $-3y^{2}+5xy$

= $2x^{2}+1$ (as $3y^{2} -5xy$ got cancelled )