Answer:
it is c
Step-by-step explanation:
B
rearrange into standard form : ax² + bx + c = 0 (a≠ 0)
2x² - 3x - 2 = 0
(x - 2)(2x + 1) = 0 ( equate each factor to zero and solve for x )
x - 2 = 0 ⇒ x = 2
2x + 1 = 0 ⇒ x = - 0.5
Answer:
B
Step-by-step explanation:
y= -24/x²+8
y-<em>i</em><em>n</em><em>t</em><em> </em><em>(</em><em> </em><em>0</em><em>,</em><em>-</em><em>3</em>
We Know that
For a function to have an inverse function, it must be one-to-one—that
is, it must pass the Horizontal Line Test.
1. On the interval [–pi/2, pi/2], the function
y = sin x is
increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full
range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is
one-to-one
sin x has an inverse function
on this interval [–pi/2, pi/2]
On the restricted domain [–pi/2, pi/2] y = sin x has a
unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x in the domain [–pi/2, pi/2] is [-1,1]
the range of y=sin-1 x in the domain [-1,1] is [–pi/2, pi/2]
1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]
On the restricted domain [0, pi] y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x in the domain [0, pi] is [-1,1]
the range of y=cos-1 x in the domain [-1,1] is [0, pi]
the answer is
<span>the values of the range are different because the domain in which the inverse function exists are different</span>
Answer:
x<-4
you need to do -5 on both sides and then divide 12 by -3 which comes out to -4 and you switch the sign because it is negative
Step-by-step explanation:
hope this helps
stay safe :))
brainliest is apppreciated
