Which order pair is a solution of the inequality 4x – 2y > 20?

1 answer:

3 0

Let's solve for all of the ordered pairs...

A. (2,-7)

4x-2y>20
4(2)-2(-7)>20
8+14>20
22>20
True

B. (-2,-7)

4x-2y>20
4(-2)-2(-7)>20
-8+14>20
6>20
Not true

C. (-2,7)
4x-2y>20
4(-2)-2(7)>20
-8-14>20
-22>20
Not true

D. (2,7)
4x-2y>20
4(2)-2(7)>20
8-14>20
-6>20
Not true

A is the correct answer

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Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

MAVERICK [17]

Answer:

The polynomial function is $x^{2} - 52$

Step-by-step explanation:

A polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ .

In this problem:

The roots are $x_{1} = 2\sqrt{13}$ and $x_{2} = -2\sqrt{13}$

Then

$(x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52$