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Luden [163]
3 years ago
13

I need help omg thanks!!!

Mathematics
2 answers:
Fudgin [204]3 years ago
5 0
I believe it’s the last option

because you would have to multiply 0.35 by c (the number of candy bars you’d sell) to get 56.
Anon25 [30]3 years ago
3 0
The last one because it is
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Which is more, 1 pound or 22 ounces?
nasty-shy [4]

Answer:

22 ounces is more

Step-by-step explanation:

1 pound is equal to 16 ounces

5 0
2 years ago
Read 2 more answers
A sales manager for an advertising agency believes that there is a relationship between the number of contacts that a salesperso
serg [7]

Using variable concepts, of dependent and independent variables, it is found that the dependent variable is the amount of sales dollars earned.

<h3>What is the relation between a function and the dependent and independent variables?</h3>

  • A function has the following format: y = f(x).
  • In which each value of y is a function of one value of x, and thus, <u>x is the independent variable and y is the dependent variable</u>.
  • That is, the input of the function is the independent variable and the output is the dependent variable.

In this problem, the manager believes that the amount of sales dollars earned is a function of the number of contacts that the salesperson makes, hence:

  • The number of contacts is the independent variable.
  • The amount of sales dollars earned is the dependent variable.

More can be learned about dependent and independent variables at brainly.com/question/1429012

#SPJ1

6 0
2 years ago
Kale can typed 165 words in 3 minutes. How can this ratio be written to show words per minute?
oee [108]

Answer:

55 words per minute

Step-by-step explanation:

165/3

7 0
4 years ago
Help please I’m not good at rational functions.
GuDViN [60]

Answer:

See below.

Step-by-step explanation:

\frac{6z^2-12z}{4z^2-16z+16} +\frac{3z}{z^2-z-2} \\\\

First, factor the numerators and the denominators:

=\frac{6z(z-2)}{4(z^2-4x+4)}+\frac{3z}{z^2-z-2}\\=\frac{6z(z-2)}{4(z-2)^2}+\frac{3z}{(z-2)(z+1)}\\=\frac{3z}{2(z-2)}+\frac{3z}{(z-2)(z+1)}

Now, make the two denominators equivalent. To do this, we can multiply the first term by (z+1) and multiply the second term by 2. This will give us:

(\frac{z+1}{z+1} )(\frac{3z}{2(z-2)})+(\frac{2}{2})(\frac{3z}{(z-2)(z+1)})\\=\frac{3z(z+1)}{2(z-2)(z+1)}+\frac{6z}{2(z-2)(z+1)}  \\

Now, combine them since they have a common denominator:

=\frac{3z^2+3z+6z}{2(z-2)(z+1)}\\ =\frac{3z^2+9z}{2(z-2)(z+1)} \\=\frac{3z(z+3)}{2(z-2)(z+1)}

This cannot be simplified further.

7 0
3 years ago
I really don’t get this , it’s graphing linear inequalities
ElenaW [278]

The first step in graphing a linear inequality is to graph the linear equality. The equation -x + 4y = -8 is equivalent to 4y = x - 8, which is equivalent to y = \frac{1}{4}x - 2. This is the equation for the line in slope-intercept form, so the line will have a slope of 1/4 and a y-intercept of -2 (see the first image). Notice that the line is solid, rather than dotted. This represents that points on the line are included in the solution, because the inequality sign is ≥, which is not a strict equality (< or >).

Next, we need to figure out which side to shade. To do so, simply pick any point (I like to use the point (0,0) because it makes the calculations easy) and see whether it satisfies the inequality. If it does, shade the side with that point, and if not, shade the opposite side of the graph.

Here we see that the point (0,0) does satisfy the inequality, since -(0) + 4(0) is 0, and 0 ≥ -8, so the top half of the graph should be shaded (see the second image).

6 0
3 years ago
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