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Studentka2010 [4]
4 years ago
6

7 more than twice a number x

Mathematics
1 answer:
torisob [31]4 years ago
5 0
So,

"7 more than"
7 +

"twice a number x"
2 * x or 2x

"7 more than twice a number x"
7 + 2x or 2x + 7
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HCF of algebraic expression x square minus y square and x y minus y square. ​
valina [46]

Answer:

(x-y+z)(x-y-z)

Given (x²-2xy+y²) - z²

= (x-y)² - z²

/* By algebraic identity

a²-2ab+b² = (a-b)² */

=[(x-y)+z][(x-y)-z]

/* a²-b² = (a+b)(a-b) */

= (x-y+z)(x-y-z)

Therefore,

(x²-2xy+y²)-z² =(x-y+z)(x-y-z)

Step-by-step explanation:

x

2

y

2

=x×x×y×y

xy

2

=x×y×y

h.c.f=xy

2

6 0
3 years ago
What is the total cost of a $53.49 meal at a restaurant after including a 12% tip?
aliya0001 [1]

Answer:

$59.9088 (or approx. $60)

Step-by-step explanation:

0.12 x $53.49

= $6.4188

$6.4188 + $53.49

= $59.9088

4 0
4 years ago
Question 3 Unsaved
bazaltina [42]

Answer:

Step-by-step explanation:

DE given is

y''+8y'+15y=0, y(0)=0, y'(0)=1

Take Laplace on the DE

We get

s^2 Y(s) -sY(0) -y'(0)+8(sY(s)-y(0))+15Y(s) =0\\s^2 Y(s) -s(0) -1+8(sY(s)-0)+15Y(s) =0\\Y(s)(s^2+8s+15)-1=0\\Y(s) = \frac{1}{s^2+8s+15}

Simplify to get

Y(s) = \frac{1}{2}[ {\frac{1}{s+3} -\frac{1}{s+5} }]

Take inverse

y(t) = \frac{e^{-3t} -e^{-5t}}{2}

8 0
3 years ago
Solve for y.<br> In(2y – 1) =
Mrrafil [7]
Answer:

~ 2y-1

Explanation:

~ There’s no like terms for us to collect

~ So we just leave it as it is, we only have to get rid of the bracket and that’s the answer
7 0
4 years ago
Can you help me please
inessss [21]
The answer is 2/4 or 1/2 :))
5 0
3 years ago
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