Answer:
(x-y+z)(x-y-z)
Given (x²-2xy+y²) - z²
= (x-y)² - z²
/* By algebraic identity
a²-2ab+b² = (a-b)² */
=[(x-y)+z][(x-y)-z]
/* a²-b² = (a+b)(a-b) */
= (x-y+z)(x-y-z)
Therefore,
(x²-2xy+y²)-z² =(x-y+z)(x-y-z)
Step-by-step explanation:
x
2
y
2
=x×x×y×y
xy
2
=x×y×y
h.c.f=xy
2
Answer:
$59.9088 (or approx. $60)
Step-by-step explanation:
0.12 x $53.49
= $6.4188
$6.4188 + $53.49
= $59.9088
Answer:
Step-by-step explanation:
DE given is
y''+8y'+15y=0, y(0)=0, y'(0)=1
Take Laplace on the DE
We get

Simplify to get
Y(s) = ![\frac{1}{2}[ {\frac{1}{s+3} -\frac{1}{s+5} }]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%20%7B%5Cfrac%7B1%7D%7Bs%2B3%7D%20-%5Cfrac%7B1%7D%7Bs%2B5%7D%20%7D%5D)
Take inverse

Answer:
~ 2y-1
Explanation:
~ There’s no like terms for us to collect
~ So we just leave it as it is, we only have to get rid of the bracket and that’s the answer
The answer is 2/4 or 1/2 :))