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3 years ago

4 (2/3) is the same as 4 groups of (2/3).

1 answer:

4 0

Answer : Yes 4(2/3) is the same as 4 groups of (2/3)

Explanation
4(2/3) requires to be multiplied and when multiplied the answer is 2 2/3. Also in 4 groups of (2/3) in order to find the total number in all the groups you have to multiply and the answer is 2 2/3 .

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The price of a house is originally listed at $155,000. The owners are having a hard time selling it and decide to reduce the pri

saul85 [17]

Answer:

83%

Step-by-step explanation:

We can put this into a fraction to get the ratio of the new price over the old price

$\frac{128650}{155000}$

This will give us the percentage of how much was decreased.

The answer you get is .83

Bring 2 decimal places to the right to get 83 (converting from decimal to percentage)

You get 83 percent to be your answer

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2 years ago

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Find the area of this triangle, round to the nearest tenth, I will give brainliest

Setler79 [48]

Answer:

59.15 in^2

Step-by-step explanation:

Using Heron's formula

semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4

Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2

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2 years ago

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A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

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3 years ago

Graph the inequality y>x-2

Anna35 [415]

Answer: 2

Step-by-step explanation:

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3 years ago

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snow_lady [41]

Answer:

the answer is: (g-f)-10

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