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xxTIMURxx [149]
3 years ago
5

Heyy! i’ll give brainliest please help.

Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0
It’s a to your question
Dahasolnce [82]3 years ago
4 0

Answer:

Weather values are ranges, while climate values are averages.

Step-by-step explanation:

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A crab-apple juice blend is mixed in a ratio of cranberry to apple 3 to 5
lord [1]

Answer:

you need to add more details

6 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
A number added to 12 and then subtracted by 18 equals 26. What is the number
tiny-mole [99]
The answer would be 32. take your 26 and add 18 then subtract 12. then rework it forward if you don't understand.
4 0
3 years ago
Read 2 more answers
Angles X and Y are congruent. Imported Asset and Imported Asset . Find the degree measure of angle X.
Sphinxa [80]
You can use a diffrent kind of ruler for math then you could find the answer.
8 0
2 years ago
Point G is (-8,6) Point J is a reflection of point G and is reflected across the x axis what are the coordinates of point J?
kakasveta [241]

Answer:

(-8, -6)

Step-by-step explanation:

Given the Point G is (-8,6) if Point J is a reflection of point G and is reflected across the x axis, to get the coordinate of point J, we will negate the y coordinate while retaining the x coordinate value

J = (-8, -(6))

J = (-8, -6)

Hence the required coordinate of J is (-8, -6)

7 0
2 years ago
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