What two numvbets are 7 units away from 0 on a number line

In the figure, one side of the rectangle divides the circle in half.

Setler79 [48]

A(rectangle)=5*12=60
A(circle)=(pi)(r^2)
r=(1/2)(5)=2.5
A(circle)=(3.14)(2.5)^2
A(circle)=19.625
Shaded Circle=1/2
(1/2)(19.625)=9.8125
A of unshaded=60-9.8125
A=50.1875 ft

6 0

4 years ago

Plssssssssssssssssssssssssssssssssss

Lostsunrise [7]

<h2>Quadrilateral</h2>

<h3>Classify the quadrilateral in as many ways as possible.</h3>

Shown in the figure, all the measurements of each sides is different, so it is only a quadrilateral. Square has four equal sides and angles, rhombus has only four equal sides, and a parallelogram whose opposite sides are parallel.

Answer:

C. Quadrilateral

Picture 1 (Rhombus)

Picture 2 (Square)

Picture 3 (Parallelogram)

Picture 4 (Quadrilateral)

Wxndy~~

3 0

2 years ago

Find the slope of the line that passes through the points (3,0) and (3,-2).

Fittoniya [83]

When given the points (x1,y1) and (x2,y2)

slope=(y2-y1)/(x2-x1)

we have
(3,0) and (3,-2)
(x,y)
x1=3
y1=0
x2=3
y2=-2

slope=(-2-0)/(3-3)=-2/0=undefined since you caon't divide by zero

answer is D

8 0

3 years ago

Read 2 more answers

Help me plz

ololo11 [35]

Answer:

$\left\{\begin{array}{l}y\le 4x\\y\ge 50\\25x+15y\ge 1975\end{array}\right.$

Step-by-step explanation:

Let x represent the number of lawns mowed and y represent the number of cars washed.

1. Since the number of cars that Beth wash is no more than four times the number of lawns Mike has scheduled to mow, you have that $y\le 4x.$ .

2. Beth will wash at least 50 cars, then $y\ge 50.$

3. Mike charges $25 each time he mows a yard, then he earns $25x for mowing x yards. Beth charges $15 for each car she washes, then she earns $15y for y cars washed. They need at least $1975, so

$25x+15y\ge 1975.$

4. A set of constraints to model the problem is

$\left\{\begin{array}{l}y\le 4x\\y\ge 50\\25x+15y\ge 1975\end{array}\right.$

4 0

3 years ago

A plane flying a straight course observes a mountain at a bearing of 30.3degrees to the right of its course. At that time the pl

Svetllana [295]

Answer:

12km or 12 kilometers

Step-by-step explanation:

We are given the following values:

For the first bearing we have:

30.3 degrees at a distance of 9 kilometers

We are asked to find the second distance of the second bearing at 40.3 degrees

Therefore, we have:

30.3 degrees = 9km

40.3 degrees = ?? Unknown( we designate this as y)

We crossmultiply

30.3 degrees × y = 9km × 40.3 degrees

Divide the both sides by 30.3 degrees

y = (9km × 40.3 degrees) ÷ 30.3 degrees

y = 362.7/30.3 degrees

y = 11.97029703 km

Approximately to the nearest tenth of a km

y = 12km.

Therefore, the distance of the plane from the mountain when the second bearing is taken (to the nearest tenth of a km) is 12km.

8 0

3 years ago