1. Number that adds up to -12 and multiplied by the same # that gives u -13. Set it up like this because both are negative so, u need 1 negative and 1 positive.
(x-13)(x+1)
2. Same rule applies. GCF
8y(4y+1)
3. (x+3)(x-3)
Answer:
322.28
A
Step-by-step explanation:
Area of the rectangle
L = 30
W = 21
Area = 30 * 21
Area = 630
Area of the circles
Radius = 7 m
Area = pi r^2
Area = 3.14 * 7^2
Area = 153.86 m^2
Area of both circles = 307.72
Area of the Shaded Region
Area of shaded region = area of the rectangle - area of 2 circles.
Area of Shaded Region = 630 - 307.72
Area of Shaded Region = 322.28
60 ≥ 35 + 5t
<u>-35 </u><u> </u><u>-35 </u>
<u>25</u> ≥ <u>5t</u>
5 5
t≤5
his mistake was that he used ≤ for at least instead of using ≥. so at end, when I solved, I saw that Sven should spend 5 minutes or less on each scale.
Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
There are no graphs available.