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3 years ago

Whats the value of 2 in the numbers 0.025

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

7 0

The value of 2 would be 0.02, or 0.020, or two hundredths.

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Use the equation below to find y, if m=2, x=8, and b=3. y=mx+b y =

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Step-by-step explanation:

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2 years ago

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grigory [225]

Answer and Step-by-step explanation:

The answer is the last answer choice.

g(x) = $-(x + 2)^2 + 1$

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The equation for a transformed function is:

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2 years ago

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2 years ago

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A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner

frozen [14]

Answer:

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner $I_{corner}$ is:

$I_{corner} = \int\limits \int\limits_R (x^2+y^2) \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx$

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(a and b are the length and the breath of the rectangle respectively )

$I_{corner} = \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx$

$I_{corner} = \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx$

$I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}$

$I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]$

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Thus; the moment of inertia of the lamina about one corner is $I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

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2 years ago