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Answer: hole at x = 0, asymptotes at x = -2 and x = -3
<u>Step-by-step explanation:</u>
= 
= 
x ≠ 0 ---> the x cancels out so this is a hole
x + 2 ≠ 0 ---> x ≠ -2 ---> asymptote at x = -2
x + 3 ≠ 0 ---> x ≠ -3 ---> asymptote at x = -3
The surface area of a cylinder is:
A=2pr^2+2prh and since r=d/2
A=2p(d^2/4+dh/2)
A=(p/2)(d^2+2dh) and we need 200 of these cylinders...
A=(100p)(d^2+2dh), and using d and h, 3.5cm and 70cm we get:
A=(100p)(3.5^2+2*3.5*7)
A=(100p)(12.25+49)
A=6125p cm^2
A≈19242 cm^2 (to nearest cm^2)
Answer:
<em>The building is 61.5 m tall</em>
Step-by-step explanation:
The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:
h = height of the building
a, b = internal angles of each triangle
x = base of each triangle
The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:
a = 90° - 37° = 53°
b = 90° - 42° = 48°
Now we apply the tangent ratio on both triangles separately:



From the last equation:

Substituting into the first equation:

Operating on the right side:

Rearranging:

Solving for h:

Calculating:
h = 61.5 m
The building is 61.5 m tall
No. The input a has multiple outputs