Find the total number of degrees in a polygon with 13 sides
1 answer:
You might be interested in
Answer:
Cos θ = -4/5
Tan θ = -3/4
Step-by-step explanation:
The question is as following:
Select the correct answer from each drop-down menu.
Angle θ lies in the second quadrant, and sin θ =3/5.
cos θ = -4/5, -3/5, 3/5, 4/5
tan θ = -4/3, -3/4, 3/4, 4/3
==================================================
Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.
If sin θ =3/5
∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.
And
Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.
F(x)=-1x-1
1) Pick 2 points on the line (i chose (-4,3) and (3,-4)
2) Find slope of the line using the 2 points. (work below)
3) Find y-intercept, which is the point where y-axis and the line cross (y-intercept is -1).
4) Place both slope and y-intercept into slope-intercept form, y=mx+b (m=slope and b=y-intercept.)
5) Change y to f(x) (meaning function of x).
Work:
3-(-4)/-4-3=3+4/-4-3=7/-7=-1
y-intercept equals -1 also.
y=mx+b
y=-1x+(-1)
y=-1x-1
f(x)=-1x-1<---Answer
1) Pick 2 points on the line (i chose (-4,3) and (3,-4)
2) Find slope of the line using the 2 points. (work below)
3) Find y-intercept, which is the point where y-axis and the line cross (y-intercept is -1).
4) Place both slope and y-intercept into slope-intercept form, y=mx+b (m=slope and b=y-intercept.)
5) Change y to f(x) (meaning function of x).
Work:
3-(-4)/-4-3=3+4/-4-3=7/-7=-1
y-intercept equals -1 also.
y=mx+b
y=-1x+(-1)
y=-1x-1
f(x)=-1x-1<---Answer