Consider an experiment in which an aluminum soft drink can and a steel soup can are left outside for a few days. Use your knowle
1 answer:
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The formula for aluminum fluoride is
That means that there is 1 Aluminum and 3 fluorde ions in 1 molecule. The 3 does not effect the Aluminum at all.
The Answer is A
Answer:
The answer is 916.67 g
Explanation:
48.0 wt% NaOH means that there are 48 g of NaOH in 100 g of solution. With this information and the molecular weight of NaOH (40 g/mol), we can calculate the number of mol there are in 100 g of this solution:
x
= 0.012 mol NaOH/100 g solution
Finally, we need 0.11 mol in 1 liter of solution to obtain a 0.11 M NaOH solution.
0.012 mol NaOH ------------ 100 g solution
0.11 mol NaOH------------------------- X
X= 0.11 mol NaOH x 100 g/ 0.012 mol NaOH= 916.67 g
We have to weigh 916.67 g of 48.0%wt NaOH and dilute it in a final volume of 1 L of water to obtain a 0.11 M NaOH solution.