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zloy xaker [14]
4 years ago
12

Algebra Ch.5 help needed

Mathematics
2 answers:
mariarad [96]4 years ago
8 0
To solve this we would need to make two equations. One equation accounts for the number of hot dogs and sandwiches and the other is the total cost

X + Y = 985

2.95x + 9.95y = 7343.75

Solve for one variable and plug it into the other equation. And solve for the next variable.

X = hotdogs
Y = sandwiches.






nikitadnepr [17]4 years ago
4 0
I just did all of them in the pictures I included so you could check your work.

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In a group of 60 students, 15 liked maths only, 20 liked science only and 5 did not liked any of two subjects. How many of them
evablogger [386]

Answer:

35

Step-by-step explanation:

Given

n (A) = 15

n (B) = 20

Students who do not like any subject = 5

Hence, number of students who would like either both or either of the two subjects = 60-5 = 55

n (A or B) = n (A) + n (B) - n (A and B)

Number of students linking both the subjects

55 - 15-20

= 55-35 = 20

Number of students linking only one subject = 60-20-5 = 35

4 0
3 years ago
7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.
blondinia [14]

\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill

\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}

7 0
2 years ago
HELP ASAP A phone company offers two monthly plans. Plan A costs $9 plus an additional $0.17 for each minute of calls. Plan B co
Slav-nsk [51]
Plan A = 9 +0.17x
Plan B = 21 +0.12x
9+0.17x = 21+0.12x
X=240
9+0.17(240)=49.8
21+0.12 (240)=49.8

240 minutes and cost $49.80 each
4 0
3 years ago
Es LOGICA PROPOSICIONAL, me pueden ayudar porfavor?
madreJ [45]

\begin{array}{c|c|c|c} p & q & \neg q & p \land \neg q \\ T & T & F & F \\ T & F & T & T \\ F & T & F & F \\ F & F & T & F \end{array}

\begin{array}{c|c|c|c} t & s & \neg t & \neg t \implies s \\ T & T & F & T \\ T & F & F & T \\ F & T & T & T \\ F & F & T & F \end{array}

\begin{array}{c|c|c}p\land \neg q & \neg t \implies s & (p \land \neg q) \implies (\neg t \implies s) \\T & T & T \\ T & F & F \\ F & T & T \\ F & F & T \end{array}

The given logical statement is false when p\land\neg q and \neg t\implies s are true and false, respectively.

  • p\land\neq g is true when p is true and q is false
  • \neg t \implies s is false when both t and s are false
6 0
2 years ago
Help with this please I'm not quite sure of the answer
kirill115 [55]

I'm pretty sure it's the first one

3 0
4 years ago
Read 2 more answers
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