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11Alexandr11 [23.1K]
2 years ago
10

Determine the equation of a line through the point (3,-4) that is perpendicular to the line y=3x+7

Mathematics
1 answer:
Lana71 [14]2 years ago
7 0

Answer:

y = - \frac{1}{3} x - 3

Step-by-step explanation:

The equation of a line in slope- intercept fprm is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 7 is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, thus

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, - 4) into the partial equation

- 4 = - 1 + c ⇒ c = - 4 + 1 = - 3

y = - \frac{1}{3} x - 3 ← equation of perpendicular line

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ExtremeBDS [4]

Answer:

1: y=-1x-3

2: y=0.8x+4.2

3: y=2x-3

Step-by-step explanation:

Question 1: When lines are parallel, that means they're slope is the same and there y-intercept is different. So the first step is to calculate the slope of BC. If you look at BC you'll notice it goes down by 2 and goes forward by 2 so the slope is -2/2 or -1. This completes one part of the slope-intercept form which is y=mx+b where m is the slope and b is the y-intercept. The y-intercept will be calculated using the point A. since the equation passes through point A

-1 = (-2)(-1) + b

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Question 2: Same concept here, if you look at AC, you'll see it "rises" by 4 and "runs" by 5, thus the slope is 4/5. Since it passes through B we'll use that to find the y-intercept

5 = (4/5)(1) + b

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Question 3: It "rises" by 6 and "runs" by 3, thus the slope is 6/3 which is 2.

Plug in known values

3=(3)(2) + b

3 = 6 + b

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8 0
2 years ago
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