The distance from third base to first base is 127.3 feet.
Answer:
<em>AB = 7.35 cm</em>
Step-by-step explanation:
From the attachment,
In ΔDEF,
DF = GH-(GD+FH) = 6 - (2+3) = 1 cm
DE = 2+3 = 5 cm (sum of two radius)
Applying Pythagoras theorem,

In ΔCDI,
DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm
CD = 2+1.5 = 3.5 cm (sum of two radius)
Applying Pythagoras theorem,

AB = EF + CI = 
I’m not 100% but my best guess is 20.
To figure out the difference you would subtract 294 from 453.
So 453-294=159
9 is linear. Rearrange to get into standard line format
2x + 3y = 5
3y = -2x + 5
y = -2/3x + 5/3
Now, plot a point at 5/3 on the y axis. Go down 2 and right 3 and put another point
Then draw a line running through both points.