Question

Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect.

Answer 1

Answer:

The area of the kite is 30 square units.

Step-by-step explanation:

Givens

$AC=10$

$BD=6$

A kite has the form of a parallelogram, so its area is defined as

$A=\frac{1}{2} \times d_{1} \times d_{1}$

Where $d_{1}$ and $d_{2}$ are the diagonals of the kite.

In this case,

$d_{1}=10$ and $d_{2}=6$

Replacing these values, we have

$A=\frac{1}{2}(10)(6)=30 u^{2}$

Therefore, the area of the kite is 30 square units.

Answer 2

Answer:

Area of kite is 30 sq units.

Solution:

Note: Refer the image attached

From the given,

AC = 10 ; BD = 6

Kite is a quadrilateral as it has two equal adjacent sides.

The formula for the area of quadrilateral (kite) when both the diagonals are given is

$\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}$

Here AC is $d_{1}$ and BD is $d_{2}$

On substituting the given values we get

$area = \frac{1}{2}\times10\times6 = \frac{60}{2}=30 sq units$