1 cm = 500km the ratio is 1 to
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To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
<h3>Number of Molecules in 2g of AlCl3</h3>The molar mass of AlCl3 is given as 133.34g/mol
Data;
- mass = 2g
- molar mass = 133.34g/mol
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.
If we equate this
From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
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