Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be

Hence, the mean and standard deviation are 567.2 and 89.88 resp.
Paying off the entire loan = 12 * 437.26 =
<span>
<span>
<span>
5,247.12
</span>
</span>
</span>
He paid 6 * 437.26 =
<span>
<span>
<span>
2,623.56
</span>
</span>
</span>
He then paid 2,556.03
2,623.56
plus = 2,556.03 =
<span>
<span>
<span>
5,179.59
</span>
</span>
</span>
<span>
<span>
5,247.12
</span>
minus </span><span>5,179.59 =
67.53 the amount of money he saved.
</span>
Answer:
(x+6i)(x-6i)(x+1)
So the zeroes are 6i, -6i, -1
Step-by-step explanation:
Factor by grouping
h(x) = x^2(x+1) + 36(x+1)
h(x) = (x^2+36)(x+1)
- Multiply (-2x-4) by -5:
[(-5)(-2x) + (-5)(-4)] +5x - 4 = -29
= 10x+20+5x-4=-29
- Combine Like Terms:
(10x+5x) + (20-4) = -29
15x+16=-29
- Subtract 16 from each side
15x+16 -16 = -29 -16
15x = -45
x = -3