The cross sectional shape is a circle.
Answer:
28.5^2
Step-by-step explanation:
The formula is, b(base)+c(height)= b+c over 2. b+c/2.
B=19ft in this problem.
C=38ft
Knowing this, we can further simplify.
19+38/2
Now, we add 19 and 38.
(57)
57/2= 28.5
So, the anwser is 28.5^2
<h3>
Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>
Work Shown:
h(y) = f(y) + g(y)
h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)
h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2
h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)
h(y) = y^4 - 2y^3 + 7y^2 + y - 5
This is a fourth degree polynomial (aka quartic).
Answer:
any score that lies between 88.8 and 97.2 is within one std. dev. of the mean
Step-by-step explanation:
One std. dev. above the mean would be 93 + 4.2, or 97.2. One std. dev. below the mean would be 93 - 4.2, or 88.8.
So: any score that lies between 88.8 and 97.2 is within one std. dev. of the mean.
Answer:
400
Step-by-step explanation:
5(1+3)^2
(5+15)^2
20^2
400
