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bogdanovich [222]
4 years ago
14

Expand the following

Mathematics
2 answers:
marissa [1.9K]4 years ago
8 0

Answer:

....

Step-by-step explanation:

Whitepunk [10]4 years ago
3 0

Answer:

Please complete the question..

Step-by-step explanation:

You might be interested in
What is the value of x?
inn [45]




MN = MA + AN =67.2m

MA + 3.2m = 67.2m

MA = 64m


Similary,

MP = 81.9


As
AB || NP

Then by Thale's theorem,

\frac{MA}{MN}  =  \frac{ MB}{MP }   \\  \\  \frac{64}{67.2}  =  \frac{x}{81.9}   \\   \\ x =  \frac{64}{62.7}  \times 81.9 = 83.59
4 0
3 years ago
A local deli makes turkey sandwiches and salami sandwiches at a weekly ratio of 2 salami sandwiches for every 5 turkey sandwiche
Dahasolnce [82]

Answer:

24

Step-by-step explanation:

Setting x as the number of salami sandwiches:

2/5 = x/60

Cross-multiplying: 5x = 2 × 60

Simplifying: 5x = 120

Division: x = 24

7 0
3 years ago
WHAT IS<br> 1+2+3+4+5=? <br> IS IT 15
Tema [17]
Yes it is 15 because 1+2 is 3 3+3=6 6+4=10 and finally 10+5=15
6 0
3 years ago
Read 2 more answers
The height of dachshuds is usually 1/3 their length. If Molly is 20 inches long how tall is she?
Llana [10]
The question is asking for 1/3 of Molly’s length, which is 20 inches. The word of in this context indicates multiplication, which means you should multiply 20 by 1/3.
1/3 x 20 = 6.666666 (repeating) or 6.7 (rounded)
Therefore, Molly is 6.7 inches tall.
6 0
3 years ago
Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel
timama [110]

Answer:

\displaystyle A=\frac{1}{192}

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

P=4x+3y

We know the total fencing is 1/2 miles long, thus

\displaystyle 4x+3y=\frac{1}{2}

Solving for x

\displaystyle x=\frac{\frac{1}{2}-3y}{4}

The total area of the pasture is

A=x.y

Substituting x

\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y

\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}

Differentiating with respect to y

\displaystyle A'=\frac{\frac{1}{2}-6y}{4}

Equate to 0

\displaystyle \frac{\frac{1}{2}-6y}{4}=0

Solving for y

\displaystyle y=\frac{1}{12}

And also

\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}

Compute the second derivative

\displaystyle A''=-\frac{3}{2}.

Since it's always negative, the point is a maximum

Thus, the maximum area is

\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}

6 0
3 years ago
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