Question

Can you help me put these into slope intercept form so I can graph them and if u can find the slope that would be great sry for bad English
1) 20x + 80y=0

2) 30x + 50y-100=0

3) 3x - 15y - 30 =0

Answer 1

Answer:

Part 1) $y=-(1/4)x$

Part 2) $y=-(3/5)x+2$

Part 3) $y=(1/5)x-2$

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

Part 1) we have

$20x+80y=0$

Simplify

Divide by 20 both sides

$x+4y=0$

isolate the variable y

Subtract x both sides

$4y=-x$

Divide by 4 both sides

$y=-(1/4)x$ ------> equation of the line into slope intercept form

$m=-(1/4)$

$b=0$

Part 2) we have

$30x+50y-100=0$

Simplify

Divide by 10 both sides

$3x+5y-10=0$

isolate the variable y

Subtract (3x-10) both sides

$5y=-(3x-10)$

Divide by 5 both sides

$y=-(3/5)x+2$ ------> equation of the line into slope intercept form

$m=-(3/5)$

$b=2$

Part 3) we have

$3x-15y-30=0$

Simplify

Divide by 3 both sides

$x-5y-10=0$

isolate the variable y

Subtract (x-10) both sides

$-5y=-(x-10)$

Divide by -5 both sides

$y=(1/5)x-2$ ------> equation of the line into slope intercept form

$m=(1/5)$

$b=-2$