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3 years ago

(p-1.7)/3.9=5.2/4 answer please

Mathematics

1 answer:

natulia [17]3 years ago

3 0

Answer:

p = 6.77

Step-by-step explanation:

p-1.7/3.9 = 5.2/4

First, you divide the numbers:

p-1.7/3.9 = 1.3

Then multiply all of the terms by the same value. That way you can eliminate the fraction denominators:

(39) p-1.7/39/10 = (39)(1.3)

Cancel out the multiplied terms that are in the denominator:

10 (p-1.7) = (39)(1.3)

Use the distrubutive property:

10p - 17 = (39)(1.3)

Multiply:

10p - 17 = 50.7

Add 17 to both sides:

10p - 17 + 17 = 50.7 + 17

Simplify:

10p = 67.7

Then divide both sides of the equation by the same term:

10p/10 = 67.7/10

Simplify by cancelling out the terms that are in both the numerator and denominator then divide the numbers:

p = 6.77

Ta-daaaa (random but I saw someone with a Gorou pfp answering this too lol)

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About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number

olganol [36]

Answer:

1) $E(X) = np = 120*0.1 =12$

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And we can use the normal approximation given by:

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And we can use the z score formula given by:

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And if we find the z score for 16 we got:

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And we can find this probability using the normal standard distribution or excel and we got:

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3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

$X\sim Binom(n= 120 , p =0.1)$

Part 1

The mean is given by:

$E(X) = np = 120*0.1 =12$

And the deviation would be:

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

$P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

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