For this case, what we must do is calculate the speed of the runner.
We have then that the speed is given by:
![v =\frac{d}{t}](https://tex.z-dn.net/?f=%20v%20%3D%5Cfrac%7Bd%7D%7Bt%7D%20%20%20)
Where,
d: distance
t: time
Substituting values we have:
![v = \frac{8}{92}](https://tex.z-dn.net/?f=%20v%20%3D%20%5Cfrac%7B8%7D%7B92%7D%20%20)
![V = 0.09 \frac{miles}{minutes}](https://tex.z-dn.net/?f=%20V%20%3D%200.09%20%5Cfrac%7Bmiles%7D%7Bminutes%7D%20%20%20)
Answer:
the runners unit rate is:
![V = 0.09 \frac{miles}{minutes}](https://tex.z-dn.net/?f=%20V%20%3D%200.09%20%5Cfrac%7Bmiles%7D%7Bminutes%7D%20%20%20)
Yes
7x6=42
8x6=48
Hope that helped :D
Answer:
Correct choice is B
Step-by-step explanation:
The exponential regression model can be written as exponential function
![y=a\cdot b^x.](https://tex.z-dn.net/?f=y%3Da%5Ccdot%20b%5Ex.)
Then
![5,000=a\cdot b^0=a,\\ \\5,510=a\cdot b^2\Rightarrow 5,510=5,000\cdot b^2,\\ \\b^2=\dfrac{5,510}{5,000}=\dfrac{551}{500}\Rightarrow b\approx 1.05.](https://tex.z-dn.net/?f=5%2C000%3Da%5Ccdot%20b%5E0%3Da%2C%5C%5C%20%5C%5C5%2C510%3Da%5Ccdot%20b%5E2%5CRightarrow%205%2C510%3D5%2C000%5Ccdot%20b%5E2%2C%5C%5C%20%5C%5Cb%5E2%3D%5Cdfrac%7B5%2C510%7D%7B5%2C000%7D%3D%5Cdfrac%7B551%7D%7B500%7D%5CRightarrow%20b%5Capprox%201.05.)
Thus,
![y=5,000\cdot (1.05)^x.](https://tex.z-dn.net/?f=y%3D5%2C000%5Ccdot%20%281.05%29%5Ex.)
When
you get
![y(12)=5,000\cdot (1.05)^{12}\approx \$8,980.](https://tex.z-dn.net/?f=y%2812%29%3D5%2C000%5Ccdot%20%281.05%29%5E%7B12%7D%5Capprox%20%5C%248%2C980.)
Answer: C. Use a larger sample size and D. Larger confidence level
Step-by-step explanation: The information will be more accurate, as it is not right now and if there are more people then there will be a huge group of people that agree on one thing.
12222x333=4069926 is the answer