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andre [41]
3 years ago
15

Solve for d.

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0
5d+2(2-d)=3(1+d)+1 \\ 5d+4-2d=3+3d+1 \\ 3d+4=3d+4 \\ 0=0 \\ \boxed{C.\ Infinitely\ many\ solutions}
r-ruslan [8.4K]3 years ago
4 0
5d + 2(2 - d) = 3(1 + d) + 1
5d + 2(2) - 2(d) = 3(1) + 3(d) + 1
5d + 4 - 2d = 3 + 3d + 1
5d - 2d + 4 = 3d + 3 + 1
3d + 4 = 3d + 4
<u>-3d       -3d        </u>
       4 = 4
       d = 0

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