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Nady [450]
3 years ago
14

What is the ratio of 3√x4

Mathematics
2 answers:
kicyunya [14]3 years ago
6 0
3\sqrt{x^4}=3x^2
Nady [450]3 years ago
5 0
I don't understand what you wrote.
Can you show a picture of the original question?
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What is three minus one
Kipish [7]

Answer:

2

Step-by-step explanation:

3 - 1 = 2

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What is the volume, in cubic inches, of a rectangular prism with a height of 19 inches, a width of 11 inches, and a length of 4
jolli1 [7]

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836

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What is the slope between the points (3, 5) and (-2, -4)
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The slope is 9/5! hope this helps!!
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3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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