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Nady [450]
3 years ago
14

What is the ratio of 3√x4

Mathematics
2 answers:
kicyunya [14]3 years ago
6 0
3\sqrt{x^4}=3x^2
Nady [450]3 years ago
5 0
I don't understand what you wrote.
Can you show a picture of the original question?
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1/4 divided by 2/3 show work pls
NARA [144]
\dfrac{1}{4}:\dfrac{2}{3}=\dfrac{1}{4}\cdot\dfrac{3}{2}=\dfrac{1\cdot3}{4\cdot2}=\boxed{\frac{3}{8}}
5 0
3 years ago
A company sells a mix of peanuts and cashews. For every 3 ounces of peanuts, there are 2 ounces of cashews. A batch has 60 ounce
shtirl [24]

Answer:

Proportion states that the two ratios or fraction are equal.

As per the given statement: For every 3 ounces of peanuts, there are 2 ounces of cashews. A batch has 60 ounces of peanuts.

Let x be the ounces of cashew will a batch have.

then by definition of proportion, we have;

\frac{3}{2} = \frac{60}{x}

By cross multiply we have;

3x = 120

Divide by 3 on both sides we get;

x = 40

therefore, 40 ounces of cashews will a batch have for every 60 ounces of peanuts.


3 0
2 years ago
Read 2 more answers
Plugging in x back in the equation which is 6, what is the measure of this alternate exterior angle
andreyandreev [35.5K]

Answer:

14x - 4 + 13x + 2

= 14(6) - 4 + 13(6) + 2

= 160

5 0
2 years ago
Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and
Jlenok [28]
We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

\frac{y}{x} = \frac{1}{8}  \\  \\ \Rightarrow x=8y \\  \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\  \\ \Rightarrow v=0

For the line with points (0, 0) and (1, 8), the equation is given by:

\frac{y}{x} = \frac{8}{1}  \\  \\ \Rightarrow y=8x \\  \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\  \\ \Rightarrow u=0

For the line with points (8, 1) and (1, 8), the equation is given by:

\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\  \\ \Rightarrow y-1=-x+8 \\  \\ \Rightarrow y=-x+9 \\  \\ \Rightarrow u+8v=-8u-v+9 \\  \\ \Rightarrow u=1-v

The Jacobian determinant is given by

\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\  \\ =64-1=63

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\  \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\  \\ =63(-9)=|-576|=576
6 0
3 years ago
lisa used 880g of a container of sugar to bake a cake and 1/10 of the creaming sugar to make cookies. She then had 3/7 of the co
guapka [62]

Answer:

At the beginning, there were 2,678.26 grams of sugar in the container.

Step-by-step explanation:

Since Lisa used 880g of a container of sugar to bake a cake and 1/10 of the creaming sugar to make cookies, and she then had 3/7 of the container of sugar left, to determine how much sugar was in the container at first, the following calculation must be performed:

880 + 1 / 10X = 3 / 7X

880 + 0.1X = 0.4285X

880 = 0.4285X - 0.1X

880 = 0.3285X

880 / 0.3285 = X

2,678.26 = X

Therefore, at the beginning there were 2,678.26 grams of sugar in the container.

3 0
2 years ago
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