Complete Questions:
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.
a. 40
b. 48
c. 56
d. 64
Answer:
a. 0.35
b. 0.43
c. 0.49
d. 0.54
Step-by-step explanation:
(a)
The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.
Let s be the sample space of all integer not exceeding 40.
The total number of ways to select 6 numbers from 40 is 
.
Let E be the event of selecting none of the correct six integers.
The total number of ways to select the 6 incorrect numbers from 34 numbers is:
Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is
Therefore, the probability is 0.35
Check the attached files for additionals
Common difference is -2-5 = -7
first term is 5
a_50 = 5 -7(50-1) = -338
2) d = 3 - (-7) = 10
a = -7
a_110 = -7 + 10(110 - 1) = 1083
d = -27 - (-22) = -5
second -7 - 5= -12
third = -12 - 5 = -17
I am not for sure how to do this just yet when I figher it out I will try to help you.<span />
Answer:
≈39.27 units
Step-by-step explanation:
To find the area of a semi circle, you use the formula for finding the area of a circle, which is 
, and then you divide that by 2 since it is half of a circle.
In this case, 
≈ 78.54
= 39.27
Answer:
Step-by-step explanation:
We are given
Let's assume it can be factored as
now, we can multiply right side
and then we can compare it
now, we can compare coefficients
now, we can find all possible factors of 48
and then we can assume possible prime factors of 48
Since, we have to find the largest value of n
So, we will get consider larger value of r because of 5r
and because n is negative of 5r+s
so, we will both n and r as negative
So, we can assume
r=-48 and s=-1
so, we get
