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3 years ago

Solve : X^2 - 3x = -8 And Solve : -2x^2 - 16x - 44 = 0

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

X = 8/3 + X^2/3

X = -4 ± i $\sqrt{6}$

Step-by-step explanation:

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1.Is the expression x3•x3•x3 equivalent to x3•3•3? Why or why not? Explain your reasoning.

Aleonysh [2.5K]

No because x3•x3•x3= 27x³ and x3•3•3=27x

7 0

3 years ago

Read 2 more answers

set the equation up for "Eight less than the square of a number is the same as adding the number and four"

TEA [102]

X^2-8 = x+4 is your answer!

5 0

4 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

Determine the rate of change of the following linear equation as it translates from (-5, -1) to any other point on the line.

Norma-Jean [14]

The rate of change of a linear equation (first degree) is equivalent to the slope of a line. Slope is described as the vertical movement (rise) of the line over its horizontal counterpart (run). In determining the rate of change or slope (m) given 1 data point (x',y'), point-slope form is applicable. Point-slope form is: (y-y') = m (x-x'). Substitute the given point (-5,-1) in the equation. By substitution, [y-(-1)] = m [x-(-5)]. Re-arranging the equation, the rate of change or slope is, m = (y+1)/(x+5).

4 0

3 years ago

Please help me!

sweet-ann [11.9K]

Answer:

bueh

Step-by-step explanation:

3 0

3 years ago