Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³
Answer:
See below.
Step-by-step explanation:
The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.
The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.
(a) h(t) = 64t - 1/2*32 t^2
h(t) = 64t - 16t^2.
(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).
The y-axis is the height of the rocket and the x-axis gives the time.
Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.
Step-by-step explanation:
Given
So
Now
So
Hope it will help :)❤
Answer:
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