Multiply the polynomials (5x^2+4x-4)(4x^3-2x+6) Explain your steps!!

1 answer:

4 0

So distribute using distributive property
a(b+c)=ab+ac so

split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24

the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24

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Find the equation of the line specified.<br> The slope is 6, and it passes through ( -4, 4).

Pie

Answer:

y=6x+28

Step-by-step explanation:

y-y1=m(x-x1)

y-4=6(x-(-4))

y-4=6(x+4)

y=6x+24+4

y=6x+28

3 0

3 years ago

Whats the equation for this

yawa3891 [41]

Answer:

$x^2 + y^2 + 4x + 4y = -119/16$

Step-by-step explanation:

The axes x and y are calibrated in 0.25

If the circle is carefully considered, the radius r of the circle is:

r = -1.25 - (-2)

r = 0.75 units

The equation of a circle is given by:

$(x - a)^2 + (y - b)^2 = r^2$

The center of the circle (a, b) = (-2, -2)

Substituting (a, b) = (-2, -2) and r = 0.75 into the given equation:

$(x - (-2))^2 + (y - (-2))^2 = (3/4)^2\\\\(x + 2)^2 + (y + 2)^2 = (3/4)^2\\\\x^2 + 4x + 4 + y^2 + 4y + 4 = 9/16\\\\x^2 + y^2 + 4x + 4y + 8 = 9/16\\\\16x^2 + 16y^2 + 64x + 64y + 128 = 9\\\\16x^2 + 16y^2 + 64x + 64y = -119\\\\x^2 + y^2 + 4x + 4y = -119/16\\$