Let the first odd integer = n
∴ The second <span>consecutive odd integer = n+2
∴ </span><span>The sum of the two integers = (n) + (n+2)
= 2n + 2
</span> The correct choice is option (D)
<span> D) 2n + 2
</span>
principal (p)=62500,Time (T)=1.5 years,Rate (R)=8% Ammount=p (1+R÷100) =62500 × 1.1664 =72900 again, compound interest = p(1+R÷100)-1=62500×0.1664 = 10400
Answer:
Step-by-step explanation:
You need to find the HCF of 36 and 90.
<u>Prime factors of each:</u>
<u>HCF includes all prime factors of both numbers:</u>
- HCF(36, 90) = 2*2*3*3*5 = 180
I = p * r * n
i is the interest
p is the principal
r is the interest rate per time period
n is the number of time periods.
in your problem:
i = 900
p = 2000
r = what you want to find
n = 3 years
formula becomes 900 = 2000 * r * 3
solve for r to get r = 900 / 2000 / 3 = .15
that's .15 interest rate per year = 15% per year.
at a nominal interest rate of .15 per year, the interest rate per month would be .15/12 = .0125 per month.
the remaining balance at the end of 6 month is equal to 1907.140183
