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3 years ago

Use a net to find the surface area of the right triangular prism shown below:

Mathematics

1 answer:

AnnZ [28]3 years ago

4 0

I don't exactly know what a net is, but I can figure out the surface area (maybe). When you put this pattern together, you have to make a couple of assumptions.
First of all the 2 triangles are connected to a base that's 8 by 13.
Base
The area of the base = 8 * 13 = 104 square feet.

Two Triangles.
The area of any triangle is
Area = 1/2 b * h
Area = 1/2 *12 * 5
Area = 30 square feet. There are 2 triangles so ...
The total area of both is 60 square feet.

Overlap
Now we come to the tough part. how big is it from the first dotted line to the second one?
The answer is 5. But why? Well the 5 comes from the the length of the side that has to be covered by this pattern. The 5 is part of the triangle.

How far across is the dotted line? The answer is 8. Why again? That's the width of the whole prism or pattern.
So the area between the two dotted lines is 5 * 8 = 40

Finally the area over the 12.
The question is how far is it from the second dotted line to the last boundary? The answer is 12. And it's width is 8
So the area = 12 * 8 = 96

Total area
96 + 60 + 40 + 104 = 300 square feet.

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Which inequality represents the statement? The ages (a) of s group of travelers all exceeded 17 years and were no more then 54 y

klasskru [66]

Answer:

The inequality that represents the age of the group, "x", is: $17 < x \leq 54$

Step-by-step explanation:

To express this problem in an inequality we will attribute the age of the members on the group with the variable "x". There are two available information about "x", the first states that every member of the group is older than 17 years, therefore we can create a inequality based on that:

$x > 17$

While the second data from the problem states that none of than is older than 54 years old, this implies that they can be at most that old, therefore the inequality that represents this is:

$x\leq 54$

In order for both to be valid at the same time x must be greater than 17 and less or equal to 54, therefore we finally have:

$17 < x \leq 54$

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3 years ago

What is the value of /E/ +/F/, A.-9 B.-11 C.11 D.9?

Furkat [3]

Answer:

Step-by-step explanation:

|E| + |F|

|1| + |-10|=11

Answer=11

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3 years ago

Gyaltsho's mass would be 32kg

adoni [48]

Answer:

What type of question is this?

Step-by-step explanation:

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3 years ago

What is the sum of £4(0.5) "1? n=1 O S=1.5 OS = 2 O S = 4.5 O S= 8

Lelu [443]

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3 years ago

What is 3/2=9/10k im having troble lots rly

tigry1 [53]

Answer:

k= 5 over 3 =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

(3)/(2)-((9)/(10)*k)=0

simplify 9/10

3 9

— - (—— • k) = 0

2 10

simplify 3/2

3 9k

— - —— = 0

2 10

Find the Least Common Multiple

The left denominator is : 2

The right denominator is : 10

Least Common Multiple:

Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 5

Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 3 • 5

—————————————————— = —————

L.C.M 10

R. Mult. • R. Num. 9k

—————————————————— = ——

L.C.M 10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k) 15 - 9k

———————————— = ———————

10 10

Pull out like factors :

15 - 9k = -3 • (3k - 5)

-3 • (3k - 5)

————————————— = 0

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

-3•(3k-5)

————————— • 10 = 0 • 10

Now, on the left hand side, the 10 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

-3 • (3k-5) = 0

Solve : -3 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solve : 3k-5 = 0

Add 5 to both sides of the equation :

3k = 5

Divide both sides of the equation by 3:

k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0

3 years ago