<u>w</u><u>=</u><u>-</u><u>1</u><u>.</u><u>5</u>
<u>w</u><u>=</u><u>2</u>
Answer:
Solution given:
again
keep square root alone
solve subtraction of 7-2
Squaring on both side
2w²-19w+31=5²-2*5*2w+4w²
take terms one side
2w²-19w+31-25+20w-4w²=0
-2w²+w+6=0
2w²-w-6=0
doing middle term factorisation
2w²-(4-3)w-6=0
2w²-4w+3w-6=0
take common from each two term
2w(w-2)+3(w-2)=0
(w-2)(2w+3)=0
either
w=2
or
W=-3/2=-1.5
Answer: C) angle 2 and angle 7
Imagine the parallel lines form the boundaries of river. Angles 3, 4, 5 and 6 are considered interior angles as they are in the river. Angles 1, 2, 7, 8, 9 and 10 are exterior because they're outside the river.
Angles 2 and 7 are on opposite sides of the transversal cut that I've highlighted in red (see diagram below). So that's why they're considered alternate. Combine "exterior" and "alternate" to get "alternate exterior"
Answer:
16
Step-by-step explanation:
To start off this problem, we are given that the line AB is equal to the line CD. In addition to that, we are given that the line EF equally intersects line AB and line CD. This provides us proof that angle AGH is equivalent to angle DHG. From this information, we can solve this problem relatively easily.
Lets work with this equation:
Next, divide 80 by 5.
This means that x is equal to 16.